Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 563 reviewsTarget Test Prep

Geometry question

Expert replies
Post new topic Post Reply
Subscribe topic
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 36
Joined: Sat Apr 14, 2007 8:06 am
by allenkt » Tue May 08, 2007 11:48 am
How would I solve this one? I can't assume it's a right triangle even though angle ABC looks to be 90 degrees. I know A = 1/2 (bh) but I'm stuck trying to find the height.
You do not have the required permissions to view the files attached to this post.
Top
Join the discussion
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Tue May 08, 2007 8:22 pm
Thanked: 1 times

by mendiratta » Tue May 08, 2007 8:55 pm
whwre's the problem figure?
Top
Join the discussion
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Tue May 08, 2007 8:22 pm
Thanked: 1 times

by mendiratta » Tue May 08, 2007 9:00 pm
I think it is sqrt(3)/2.
Angle subtended by diameter is always 90 degree.
So it is right angled triangle with 2 sides as 1 & 2(twice the radius).
There the third side is sqrt(3). ( 1,2,sqrt(3) ) kind of triangle.
therefore
area = (base*height)/2
area = ( sqrt(3) * 1 )/2
area = sqrt(3)/2.
Top
Join the discussion
Legendary Member
Posts: 559
Joined: Tue Mar 27, 2007 1:29 amFollowed by: 2 members
Thanked: 5 times

by Cybermusings » Sat May 12, 2007 2:41 am
Remember the theorem for your exam...An angle in a semicircle is a right-angle...

Here angle ABC is a right angle...

AC = Diameter = 2
BC = 1
So AB = sqr rt. 3
Now Area = 1/2 * sqr rt 3 * 1 = sqr rt. 3/ 2

Hence Choice C
Top
Join the discussion