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Geometry Question II

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Geometry Question II

by sandeep_chhabra » Thu May 15, 2008 2:59 am
Need some help on this:


Image


Thanks !
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by mwilliams » Thu May 15, 2008 5:08 am
edit: cleared
Last edited by mwilliams on Mon Jan 31, 2011 12:05 pm, edited 1 time in total.
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by aatech » Thu May 15, 2008 6:06 am
ANS B

Think of the image as 2 triangles..

First - PR as Base and QR as height

Second - PQ as Base and SR as height

Stmt 1 - Does not give you info about RS so insuff

Stmt 2 - PQ*QR = 12 => Area of triangle = 6

Area of a triangle is (Base*Height)/2 = (PR*QR)/2 = (PQ*SR)/2 = 6

So, PQ*SR = 12 SUFF
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