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geometry in DS...

Expert replies
Source: — Data Sufficiency |

by gmatclubmember » Tue Sep 06, 2011 6:57 am
mukgera wrote:In the xy-plane, does the line with equation y = 3x + 2 contains the point (r,s)?

1) (3r+2-s)(4r+9-s) = 0
2) (4r-6-s)(3r+2-s) = 0

OA after some discussion.[/quote-

---------------
r and s should satisfy the eqution of line. so s=3r+2.
Put that value in 1 and it satisfy the condition.
Similary put the same value in 2 and it too satisfy the condition.

So both statements are sufficient to answer the question.

D.
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by Brent@GMATPrepNow » Tue Sep 06, 2011 7:10 am
mukgera wrote:In the xy-plane, does the line with equation y = 3x + 2 contains the point (r,s)?
1) (3r+2-s)(4r+9-s) = 0
2) (4r-6-s)(3r+2-s) = 0
If (r,s) is on the line, then it must be the case that s = 3r+2
So, the target question can be reworded as "Does s = 3r+2"

(1) If (3r+2-s)(4r+9-s) = 0, then either a) 3r+2-s = 0 or b) 4r+9-s = 0

a) If 3r+2-s = 0 then s = 3r+2 (yes!)
b) If 4r+9-s = 0 then s= 4r+9 (no!)
Insufficient

(2) If (4r-6-s)(3r+2-s) = 0, then either c) 4r-6-s or d) 3r+2-s = 0
c) If 4r-6-s=0 then s = 4r-6 (no!)
d) If 3r+2-s = 0 then s = 3r+2 (yes!)
Insufficient

If statements (1) and (2) are true, then it must be the case that s = 3r+2, in which case (r,s) IS on the line.

Answer is C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by gmatclubmember » Tue Sep 06, 2011 7:27 am
Brent@GMATPrepNow wrote:
mukgera wrote:In the xy-plane, does the line with equation y = 3x + 2 contains the point (r,s)?
1) (3r+2-s)(4r+9-s) = 0
2) (4r-6-s)(3r+2-s) = 0
If (r,s) is on the line, then it must be the case that s = 3r+2
So, the target question can be reworded as "Does s = 3r+2"

(1) If (3r+2-s)(4r+9-s) = 0, then either a) 3r+2-s = 0 or b) 4r+9-s = 0

a) If 3r+2-s = 0 then s = 3r+2 (yes!)
b) If 4r+9-s = 0 then s= 4r+9 (no!)
Insufficient

(2) If (4r-6-s)(3r+2-s) = 0, then either c) 4r-6-s or d) 3r+2-s = 0
c) If 4r-6-s=0 then s = 4r-6 (no!)
d) If 3r+2-s = 0 then s = 3r+2 (yes!)
Insufficient

If statements (1) and (2) are true, then it must be the case that s = 3r+2, in which case (r,s) IS on the line.

Answer is C

Cheers,
Brent

Thanks for pointing out my mistake.
In this case we would need both the conditions to arrive at the conclusion that s = 3r+2 and so the answer should be C.

(3r+2-s)(4r+9-s) = (4r-6-s)(3r+2-s) , if 3r+2-s!=0 then 9=-6 which is incorrect so 3r+2-s has to be 0 and then it would satisfy the equation.

Is that correct.
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by Brent@GMATPrepNow » Tue Sep 06, 2011 7:37 am
(3r+2-s)(4r+9-s) = (4r-6-s)(3r+2-s) , if 3r+2-s!=0 then 9=-6 which is incorrect so 3r+2-s has to be 0 and then it would satisfy the equation.
You're absolutely correct, gmatclubmember.

Although, for the benefit of others, I should point out that by "!=0" you mean "not equal to zero".

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by mukgera » Tue Sep 06, 2011 8:53 am
Thanks Brent for this wonderful explanation...OA is C
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