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by rabab » Sun Nov 09, 2008 9:00 am
Can anyone help solving the following 2 questions?

https://img366.imageshack.us/my.php?imag ... 249zn6.jpg

https://img508.imageshack.us/my.php?imag ... 578ls0.jpg

Help, anyone?
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by sgarnepudi » Sun Nov 09, 2008 9:25 am
If could try the second one .. pls confirm if its correct or not ..

as its an eqilateral triangle all the arcs will be same so there will be 4 arcs total.. if 3arcs = 24 perimeter is 32 = 2*Phi*r so r is approx 5.9 * 2 = 11 apprx is the diameter.
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by rabab » Sun Nov 09, 2008 10:02 am
sgarnepudi wrote:If could try the second one .. pls confirm if its correct or not ..

as its an eqilateral triangle all the arcs will be same so there will be 4 arcs total.. if 3arcs = 24 perimeter is 32 = 2*Phi*r so r is approx 5.9 * 2 = 11 apprx is the diameter.

Oh yes, the answer is 11. Thank you.

Can anyone help with the Q no 1 pls?
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by stop@800 » Sun Nov 09, 2008 10:13 am
rabab wrote:
sgarnepudi wrote:If could try the second one .. pls confirm if its correct or not ..

as its an eqilateral triangle all the arcs will be same so there will be 4 arcs total.. if 3arcs = 24 perimeter is 32 = 2*Phi*r so r is approx 5.9 * 2 = 11 apprx is the diameter.

Oh yes, the answer is 11. Thank you.

Can anyone help with the Q no 1 pls?
lines are perpendicular so product of slopes = -1

-1/sqrt(3) * t/s = -1

t = sqrt(3) * s

from OP
radius = 2

hence
s^2 + t^2 = 4
s^2 + 3s^2 = 4

s= + - 1
take +ve

Hope this helps...
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by earth@work » Wed Nov 12, 2008 5:32 pm
question 1:
let PQ intersect y-axis at D , pyth. theorem on triangle POD gives radius=2
now cos POX' = (sq root 3)/2=cos 30
we get angle QOX=60 Degree
cos 60 = s/2=1/2
therefore, s=1
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