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Geometry DS 2- GMAT PREP

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Senior | Next Rank: 100 Posts
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by GMATDUD » Fri Feb 08, 2008 9:48 am
Hi PPl.


On condition 2 I could not figure out a line with a negative y intercept and a negative slope running into the I quadrant to intersect at point (4,3). Is it possible ?
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Source: — Data Sufficiency |
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by arawamis » Sat Feb 09, 2008 11:49 am
Consider (1) only:
x/y and 1/3's LC denom is 6. So y can be 2 or 6 (minimum). Indeed x/y can also be for example 18/36 can can satisfy (1) after simplification. NOT SUFFICIENT

Consider (2) only:
x=1. no info regarding y's value available wahtsoever NOT SUFFICIENT

Consider (1) and (2) together:
So, x/y can be 1/2 or 1/6. NOT SUFFICIENT
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