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Geometry - center of ceiling to farthest pt in a room

Expert replies
by goalevan » Sat Jan 10, 2009 5:00 pm
Can anybody give me the answer for this fairly simple problem?

I'm coming up with 16, but I must be missing something because this isn't an available choice. Maybe there was a mistype in the book... it's from Manhattan's GMAT Guide.


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Source: — Problem Solving |

so the height = x = 12

then you have 12 - 8 rectangle in the bottom the mid point has a triangle with sides 12/2 and 8/2 = 6 and 4

so the diagonal is is SQRT(6^+4^2) = SQRT(52)

the closest distance is than the right angle triangle with sides SQRT(52) and 12

Answer is SQRT [ SQRT(52) ^2 + 12^2] = SQRT196 = 14

I dont think this question is "fairly" simple by the way :) You have to know your space geometry and play with a rectangular box during your spare time :)
LGTCH
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Diagram for understanding

by kanha81 » Sat Jan 10, 2009 7:13 pm
Logitech,

Grateful, if you can please include a rough sketch or diagram for understanding purposes. I would really appreciate that, especially with the geometry problems. I have a hard time grasping the concepts.

Best regards.
Want to Beat GMAT.
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Re: Diagram for understanding

by logitech » Sat Jan 10, 2009 7:52 pm
kanha81 wrote:Logitech,

Grateful, if you can please include a rough sketch or diagram for understanding purposes. I would really appreciate that, especially with the geometry problems. I have a hard time grasping the concepts.

Best regards.
Sure thing. Let me know if you still have doubts.
You do not have the required permissions to view the files attached to this post.
LGTCH
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"DON'T LET ANYONE STEAL YOUR DREAM!"
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by goalevan » Sat Jan 10, 2009 8:44 pm
Having recently started my studying, for some reason I had thought sqrt(196) was equal to 16. I have forgotten more than I expected! Thank you Logitech, really appreciate the help.
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