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by vipulgoyal » Mon Jan 20, 2014 10:04 pm
The figure shows a frustum of a cone. If r=3, R=6, and h=4, what is the side surface area of the frustum?
(A) 15pi
(B) 30pi
(C) 36pi
(D) 45pi
(E) 60pi

please refer attachment
D
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by theCodeToGMAT » Tue Jan 21, 2014 3:08 am
[spoiler]{D}[/spoiler]
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by ceilidh.erickson » Wed Jan 22, 2014 11:31 am
This is not a question that you would see on the GMAT. 3-dimensional geometry on the GMAT is limited to just cylinders and rectangular boxes. You will not see cones, and you will certainly not encounter the word "frustum."

Please do not study from non-GMAT-like sources!
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