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Source: — Data Sufficiency |
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by maihuna » Mon Jan 31, 2011 9:09 am
yes because the two trianle will be symmetric or same size
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by Anurag@Gurome » Mon Jan 31, 2011 10:30 am
yellowho wrote:If you know that AB=BC, can you say z = k?
If AB = BC, then in ∆ABD and ∆CBD,
  • AB = BC
    BD is common side
    angle ABD = angle CBD = right angle
Hence, the triangle are congruent, i.e. the lengths of their corresponding sides and measures are corresponding angles are same. Hence, z = k. Also x = y.

For more details on congruent triangles, consult any standard geometry book or visit https://www.onlinemathlearning.com/congr ... ngles.html or https://staff.argyll.epsb.ca/jreed/math9 ... gruent.htm
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by yellowho » Mon Jan 31, 2011 9:59 pm
Thanks. Can you look at this similar problem. Here, AO=OC because both are radius but the answer suggests that you CANNOT assume that Z=Y because AO=OC. I know you are right and the answer is right so what am I missing here? What's the difference?


[quote="Anurag@Gurome"][quote="yellowho"]If you know that AB=BC, can you say z = k?[/quote]
If AB = BC, then in ∆ABD and ∆CBD,
[list]AB = BC
BD is common side
angle ABD = angle CBD = right angle[/list]
Hence, the triangle are congruent, i.e. the lengths of their corresponding sides and measures are corresponding angles are same. Hence, z = k. Also x = y.

For more details on congruent triangles, consult any standard geometry book or visit [url]https://www.onlinemathlearning.com/congr ... ngles.html[/url] or [url]https://staff.argyll.epsb.ca/jreed/math9 ... gruent.htm[/url][/quote]
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by Anurag@Gurome » Mon Jan 31, 2011 10:03 pm
yellowho wrote:What's the difference?
The difference is in the original problem, BD was perpendicular on AC, bu here OB is not perpendicular to AC.
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by yellowho » Mon Jan 31, 2011 10:06 pm
Got it thanks. So in a triangle if two sides are equal than its corresponding angles are equal and the converse. But here, since you essentially have two different triangles, you cant apply that rule?


[quote="Anurag@Gurome"][quote="yellowho"]What's the difference?[/quote]

The difference is in the original problem, BD was perpendicular on AC, bu here OB is not perpendicular to AC.[/quote]
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