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Source: — Problem Solving |
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by ajith » Thu Feb 18, 2010 5:14 am
Giorgio wrote:if F(X+Y)=F(x)F(y) what is F(0) ?

10

1

0

-1

-10
F(0+0) = F(0)*F(0)

F(0) = F(0)^2

F(0) = 1 or 0

It could be either
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by harsh.champ » Thu Feb 18, 2010 1:35 pm
Giorgio wrote:if F(X+Y)=F(x)F(y) what is F(0) ?

10

1

0

-1

-10
My take on the question will be:-
Lets say x=0 and y=1
Then,F(0+1)=F(0)F(1)
=>F(1) = F(0)F(1)
=>F(1)[F(0) - 1] = 0
Hence,either [spoiler]F(1) = 0 or F(0) = 1.[/spoiler]
Hence the option would be B.
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by ajith » Thu Feb 18, 2010 1:39 pm
The answer Could B or C ie 1 or 0
Source and OA please
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by shashank.ism » Sun Feb 21, 2010 3:39 pm
Giorgio wrote:if F(X+Y)=F(x)F(y) what is F(0) ?

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1

0

-1

-10
F(X+Y)=F(x)F(y) -putting x= 0 , y = 1, we get F(0+1) = F(0) F(1)--->( f(0)-1)f1 =0 --> [spoiler]f(0) Ans D[/spoiler]
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by onedayi'll » Sun Feb 21, 2010 9:01 pm
shashank.ism wrote:
Giorgio wrote:if F(X+Y)=F(x)F(y) what is F(0) ?

10

1

0

-1

-10
F(X+Y)=F(x)F(y) -putting x= 0 , y = 1, we get F(0+1) = F(0) F(1)--->( f(0)-1)f1 =0 --> [spoiler]f(0) Ans D[/spoiler]


Dude,

How can you conclude D as answer from ( f(0)-1)f1 =0

either f1 =0
or f(0) = 1
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by ashforgmat » Sun Feb 21, 2010 9:40 pm
Dunno ...but as a guess
Also :-

F(1+0) = F(1). F(0)
[spoiler]F(1) = F(1) => F(0) = 1

Hence My answer is B [/spoiler]
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