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functions f(a + b) = f(a) + f(b) for all positive numbers...

Expert replies
by galinaphillips » Sat Jun 02, 2007 4:44 am
My question is how to solve this problem from the MBA.com software test 1:

For which of the following functions is f(a + b) = f(a) + f(b) for all positive numbers a and b?

Possible answers are:

f(x) = x^2

f(x) = x + 1

f(x) = sqrt x

f(x) = 2/x

f(x) = -3x

The correct answer is f(x) = -3x but I'm not sure how to solve.

Thanks!
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Source: — Problem Solving |

by mschling52 » Sat Jun 02, 2007 12:02 pm
The approach I would take is to plug in a+b in place of x into each function (this is f(a+b)) then see if you can rearrange to get something equal to f(a)+f(b).

A. f(a+b) = (a+b)^2 = a^2 + 2ab + b^2 = f(a)+f(b)+2ab
B. f(a+b) = a + b + 1 = f(b) + a
C. f(a+b) = sqrt(a+b) not equal f(a)+f(b) = sqrt(a)+sqrt(b)
D. f(a+b) = 2/(a+b) not equal f(a)+f(b) = 2/a + 2/b
E. f(a+b) = -3(a+b) = -3a+-3b = f(a)+f(b)
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Thanks a lot! It was very helpful. :)
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