thats not possible.. I believe there is type in option cbillyr wrote:For which the functions f is f(x)=f(x-1) for all x?
a)f(x)=1-x
b)f(x)=1-x^2
c)f(x)=x^2 (1-x^2)
d)f(x)=x^2+1
The answer is c
thanks
Answer would be C only if option : x^2 (1-x)^2
thats not possible.. I believe there is type in option cbillyr wrote:For which the functions f is f(x)=f(x-1) for all x?
a)f(x)=1-x
b)f(x)=1-x^2
c)f(x)=x^2 (1-x^2)
d)f(x)=x^2+1
The answer is c
thanks