Pepeprepa- I think you're answering a different question from what's intended (or at least that's what I'm guessing, based on the answer choices). You are assuming that (x-7) is under the square root, and I'm quite sure it's not supposed to be. That is, you're assuming the function is:pepeprepa wrote:That's long compared to what the question requires but it will perhaps explain it to you more concretely.
You need what is in the square root to be 0 or positive.
If you take x=2 or x<2 it is ok because numerator and denumerator are negative so it gives you a positive result.
If we want both numerator and denumerator to be positive, we need x to be at least equal to 8 (7 is impossible given x-7 at the denumerator).
So you can draw this line:
-------------2--------------7-----8---------------
x must be: x<=2 and x>=8
The domain of a function of x (i.e. f(x)) is all the possible values of x.vishubn wrote:hi Ian
I understood the discussion , but i would like to know wat exactly he word " Domain" means in context of value F(x) given here ??
I just didnt get that part :
Vishu
has a domain of all positive integers.For all positive integers x, f(x) = 3(rootx) + 6
If F(x)= root(x-2)/(x-7), which of the following is a possible value of x?
