Ankitaverma wrote:If 1/2 of the air in a tank is removed with each stroke of a vacuum pump, what fraction of the original amount of air has been removed after 4 strokes?
(A) 15/16
(B) 7/8
(C) 1/4
(D) 1/8
(E) 1/16
Q/A-a
The amount of air is reduced by 1/2 four times.
Plug in a value that can be divided by 2 four times.
Let the original amount of air = 2� = 16 units.
After 1 stroke, the remaining amount of air = 8 units.
After 2 strokes, the remaining amount of air = 4 units.
After 3 strokes, the remaining amount of air = 2 units.
After 4 strokes, the remaining amount of air = 1 unit.
.
Since only 1 unit remains, the amount removed = 15 units.
(amount removed)/(original amount) = 15/16.
The correct answer is
A.
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