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Fractions Problem

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by iikarthik » Thu Jun 03, 2010 7:24 pm
Hi,

It would great if someone could post the explanation.

Thanks
karthik

A has $18 more than what B & C together would have had if both B and C had 1/4 of what A has. How much does A have?

(A) 20

(B) 48

(C) 32

(D) 36

(E) 40

OA is D
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by krazy800 » Thu Jun 03, 2010 7:29 pm
iikarthik wrote:Hi,

It would great if someone could post the explanation.

Thanks
karthik

A has $18 more than what B & C together would have had if both B and C had 1/4 of what A has. How much does A have?

(A) 20

(B) 48

(C) 32

(D) 36

(E) 40

OA is D


Here

A = 18 + (B+C)

B=C=1/4 (A)

B+C = (1/2) A

A = 18 + (1/2)A

1/2 (A) = 18

A =36

D

HTH
Aiming High
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by liferocks » Thu Jun 03, 2010 7:31 pm
question is A has $18 more than what B & C together would have had if both B and C had 1/4 of what A has

if both B and C had 1/4 of what A then they would have 1/2 of what A has and that is $18 less than total amount of A

so 1/2 of what A has =$18
or A has 18*2=$36

Ans option D
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