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Fraction - Scooter

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by pullagurla » Wed Jul 14, 2010 10:19 am
A scooter before overhauling requires 2/3 hour service time for every 45 days , while overhauling it requires 2/3 hour service time for every 60 days. what fraction of pre-overhauling service time saved in the latter case ?
a.4/3
b.1/3
c.1/4
d.3/4
e.4/9
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by kvcpk » Wed Jul 14, 2010 10:35 am
pullagurla wrote:A scooter before overhauling requires 2/3 hour service time for every 45 days , while overhauling it requires 2/3 hour service time for every 60 days. what fraction of pre-overhauling service time saved in the latter case ?
a.4/3
b.1/3
c.1/4
d.3/4
e.4/9
before 45 days -> 2h/3
after 60 days -> 2h/3
saved time is 15 days
15/45 time is saved.
1/3
pick B
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by indiantiger » Fri Jul 16, 2010 8:11 am
before overhauling would require service every 45,90,135,180 days..
after overhauling it would require service every 60,120,180 days..

As we can see that 180 is common in the series giving as a common ground (multiple) to compare the two

before overhauling the total time spent in service = (2/3) *60 minutes * 4 = 160 minutes
after overhauling the total time spent in service = 2/3 * 60 * 3 = 120 minutes

fraction of pre-overhauling service time saved in the latter case = 160-120 / 160 = 40/160 = 1/4 (ANSWER is D)
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by kmittal82 » Fri Jul 16, 2010 8:25 am
Here's my method:

Total time saved = 15 days.

Pre-overhauling, 45 days costs 2/3 hours of service, so 15 days would've cost 2/9 hours of service. Hence, we saved 2/9 hours.

what fraction of 2/3 is 2/9?

2/3 x = 2/9 => x = 1/3
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by indiantiger » Sat Jul 17, 2010 8:21 am
whats the OA?
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