oex85 wrote:If xy=1, what is the value of 2^(〖(x+y)〗^2 )/2^(〖(x-y)〗^2 ) ?

Correct me if I'm wrong, I guess the expression is [2^(x + y)²]/[2^(x - y)²]...

Now, the expression [2^(x + y)²]/[2^(x - y)²] is equivalent to 2^[(x + y)²] - (x - y)²].

Hence, [2^(x + y)²]/[2^(x - y)²] = 2^[(x + y)²] - (x - y)²] = 2^[(x² + 2xy + y²) - (x² - 2xy + y²)] = 2^[4xy] = 2^4 = 16

The correct answer is D.

PS : You can easily post the equation in correct form by using brackets and parentheses properly. In this case you could've done that by posting the expression as [2^{(x + y)^2}]/[2^{(x - y)^2}]