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Fraction problem

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by tuscan21 » Fri Mar 27, 2009 4:42 am
A certain fraction is equivalent to 2/5. If the numerator of the fraction is increased by 4 and the denominator is doubled, the new fraction is equivalent to 1/3.
What is the sum of the numerator and denominator of the original fraction?

(A) 49
(B) 35
(C) 28
(D) 26
(E) 21
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Re: Fraction problem

by Vemuri » Fri Mar 27, 2009 5:11 am
A certain fraction is equivalent to 2/5, i.e. 2x/5x, where x is any integer.
The question states that numerator is increased by 4 & denominator is doubled, i.e (2x+4)/(2*5x) = 1/3 ==> (2x+4)/10x = 1/3. Solving for x, we get x = 3. Substitute x in the orginial fraction & add the numerator value with denominator value, i.e. 2*3+5*3=21.

E is the answer. Hope this helps.

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Last edited by Vemuri on Fri Mar 27, 2009 9:32 am, edited 1 time in total.
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Re: Fraction problem

by shibal » Fri Mar 27, 2009 6:48 am
Vemuri wrote:A certain fraction is equivalent to 2/5, i.e. 2x/5x, where x is any integer.
The question states that numerator is increased by 4 & denominator is doubled, i.e (2x+4)/(2*5x) = 1/3 ==> (2x+4)/10x = 1/3. Solving for x, we get x = 3. Substitute x in the orginial fraction & add the numerator value with denominator value, i.e. 2*3+5*3=21.

D is the answer. Hope this helps.

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21 is (E) =P....
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Re: Fraction problem

by Vemuri » Fri Mar 27, 2009 9:32 am
shibal wrote: 21 is (E) =P....
Thanks for correcting Shibal :-)
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