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Four families of three are lining up for a photo. How many ways can they line up if all of the members in each family

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C

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Four families of three are lining up for a photo. How many ways can they line up if all of the members in each family must stand together?

A. \(12\)

B. \(4!3!\)

C. \(7!\)

D. \(4!6^4\)

E. \(12!\)

The OA is D
Source: — Problem Solving |