Four dollar amounts, w, x, y, and z

linfongyu wrote:Four dollar amounts, w, x, y, and z, were invested in a business. Which amount was greatest?

1. y < z < x
2. x was 25 percent of the total of the four investments.

OA to follow shortly.

From the original, we have no info at all, so we need to just jump into the statements.

(1) nothing about w, so insufficient.

(2) nothing about the relationship bewteen x and the other amounts, so insufficient (and not a big enough % for x; for example if we knew that x was 51% of the total, (2) would have been sufficient alone).

Together:

From (1), we know that either x or w is the biggest amount.

From (2), we know that x is exactly 25%.

Well, if x is bigger than y and z, then each of them must be less than 25%.

So, since w + x + y + z = 100%, we can substitute in:

w + 25% + (less than 25%) + (less than 25%) = 100

and solving for w:

w = 75% - (less than 50%)

Accordingly, w must be more than 25% and is the greatest amount: choose C.

Can we use number picking for this DS

Statement 1:
y<z<x
100<200<500

Statement 1 by itself is not Sufficient.

Statement 2:

x=.25(x+y+z+w)

Clearly Statment 2 by itself is also not enough.
Because if x=100,y=100,z=100,w=100 will satisfy the condition, and surely there are numerous possibilities to choose any of the investements to be big.

From 1 & 2 how ever.

500=25/100(100+200+500+w)
W=1200

Hence C wins.