Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

For integers x and y, when x is divided by y, the remainder is odd. Which of the following must be true?

Expert replies
by BTGModeratorVI » Wed Feb 03, 2021 10:38 am
Timer
00:00
Your answer
Difficulty–

right wrong

Pick an answer to see how members did

For integers x and y, when x is divided by y, the remainder is odd. Which of the following must be true?

A. x is odd
B. xy is odd
C. x and y share no common factors other than 1
D. The sum x + y is odd
E. At least one of x and y is odd

Answer: E
Source: Veritas Prep
Join the discussion
Source: — Problem Solving |

BTGModeratorVI wrote: ↑
Wed Feb 03, 2021 10:38 am
For integers x and y, when x is divided by y, the remainder is odd. Which of the following must be true?

A. x is odd
B. xy is odd
C. x and y share no common factors other than 1
D. The sum x + y is odd
E. At least one of x and y is odd

Answer: E
Source: Veritas Prep
Since, the question asks "Which of the following must be true?", we can eliminate any answer choice that is not necessarily true.
So let's test some values that satisfy the given conditions

For integers x and y, when x is divided by y, the remainder is odd.
One possible case is that x = 9 and y = 6 (since 9 divided by 6 leaves remainder 3)
Check the answer choices . . .
ELIMINATE B, since xy = 54, which is EVEN
ELIMINATE C, since 9 and 6 have a common factor of 3


Another possible case is that x = 6 and y = 5 (since 6 divided by 5 leaves remainder 1)
Check the answer choices . . .
ELIMINATE A since x is EVEN


Another possible case is that x = 11 and y = 5 (since 11 divided by 5 leaves remainder 1)
Check the answer choices . . .
ELIMINATE D since x is x + y = 16, which is EVEN

By the process of elimination, the correct answer is E
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

BTGModeratorVI wrote: ↑
Wed Feb 03, 2021 10:38 am
For integers x and y, when x is divided by y, the remainder is odd. Which of the following must be true?

A. x is odd
B. xy is odd
C. x and y share no common factors other than 1
D. The sum x + y is odd
E. At least one of x and y is odd

Answer: E
Source: Veritas Prep
Let \(X=nY+R\) (\(n=\) some quotient, \(R=\)remainder)

or \(X=nY+2k+1\) (\(2k+1=\)odd remainder)

Now if \(Y\) is even;

\(X=nY+2k+1=\)even\(+\)even\(+1=\)odd

and if \(Y\) is odd;

\(X=\)(odd or even)\(+\)(even)\(+1\)
\(=\)(odd or even)

So, at least \(1\) of \(X\) and \(Y\) will always be Odd.
Join the discussion