For how many integers $n$ is $n + n = n\cdot n ?$ a) None b) One c) Two d) Three e) More than three. [spoiler]OA=C[/spoiler] Source: Veritas Prep

Vincen wrote: ↑Mon May 11, 2020 3:28 am For how many integers $n$ is $n + n = n\cdot n ?$ a) None b) One c) Two d) Three e) More than three. [spoiler]OA=C[/spoiler] Source: Veritas Prep Given: n + n = (n)(n) Simplify both sides: 2n = n² Subtract 2n from both sides to get: 0 = n² - 2n In other words: n² - 2n = 0 Factor to get: n(n - 2) = 0 So, either n = 0 or n = 2 There are two solutions Answer: C Cheers, Brent

Vincen wrote: ↑Mon May 11, 2020 3:28 am For how many integers $n$ is $n + n = n\cdot n ?$ a) None b) One c) Two d) Three e) More than three. [spoiler]OA=C[/spoiler] Simplifying the equation, we have: 2n = n^2 n^2 - 2n = 0 n(n - 2) = 0 n = 0 or n = 2 We see that there are two such values. Answer: C

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