Since @m=3m when m is odd, @9 = 3*9 = 27.For all positive integers m, @m=3m when m is odd and @m=(1/2)m when m is even. Which of the following is equivalent to @9 x @6?
A - @81
B - @59
C - @36
D - @27
E - @18
How is the answer 27?Please explainGMATGuruNY wrote:Since @m=3m when m is odd, @9 = 3*9 = 27.For all positive integers m, @m=3m when m is odd and @m=(1/2)m when m is even. Which of the following is equivalent to @9 x @6?
A - @81
B - @59
C - @36
D - @27
E - @18
Since @m=(1/2)m when m is even, @6 = (1/2)6 = 3.
Thus, @9 * @6 = 27*3 = 81.
Notice the @ symbol in the answer choices.
The correct answer must be the EQUIVALENT of 81.
Answer choice D: @27
Since @m=3m when m is odd, @27 = 3*27 = 81.
The correct answer is D.
Answer choice A is A TRAP.
Always beware of an answer choice that seems TOO EASY or TOO OBVIOUS.
We are given that [m] = 3m when m is odd, and [m] = (1/2)*m when m is even, and we must determine the value of [9]*[6].rakeshd347 wrote:For all positive integers m, [m]=3m when m is odd and [m]=(1/2)*m when m is even. What is [9]*[6] equivalent to?
A. [81]
B. [54]
C. [37]
D. [27]
E. [18]
9 is odd, so [9] = (3)(9) = 27[m] = 3m for all odd m; [m] = (1/2)(m) for all even m. solve [9] X [6]?
A. [81]
B. [54]
C. [37]
D. [27]
E. [18]
Brent@GMATPrepNow wrote:9 is odd, so [9] = (3)(9) = 27[m] = 3m for all odd m; [m] = (1/2)(m) for all even m. solve [9] X [6]?
A. [81]
B. [54]
C. [37]
D. [27]
E. [18]
6 is even, so [6] = 6/2 = 3
So, [9] x [6] = 27 x 3 = 81
BEFORE you select A, notice that 81 has brackets around it.
Since 81 is odd, [81] = (3)(81) = 243
So, answer choice A is NOT correct.
So, which of the 5 answer choices equals 81?
Since 27 is odd, [27] = (3)(27) = 81
So, the correct answer is D
Cheers,
Brent
