Five friends play blackjack in Las Vegas and lose an average

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BTGmoderatorDC: Moderator; Posts: 7187; Joined: Thu Sep 07, 2017 4:43 pm; Followed by:23 members

Five friends play blackjack in Las Vegas and lose an average

by BTGmoderatorDC » Sun Mar 10, 2019 1:59 am

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Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900

OA A

Source: Princeton Review

Source: Beat The GMAT — Problem Solving | Sun Mar 10, 2019 1:59 am

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by [email protected] » Mon Mar 11, 2019 11:38 am

Hi All,

We're told that 5 friends play blackjack in Las Vegas and lose an AVERAGE of $100 each - with the losses of two of the friends totaling $380. We're asked for the AVERAGE loss of the other 3 friends. This question is a standard Average Formula question and requires just a bit or Arithmetic to solve.

To start, if 5 friends had an AVERAGE loss of $100 each, then the TOTAL loss was (Total)/5 = $100 --> Total = $500

The losses from 2 of the friends totaled $380, so the remaining loss would be $500 - $380 = $120.

That loss, when averaged over the remaining 3 friends, is... $120/3 = $40 each

Final Answer: A

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by Scott@TargetTestPrep » Thu Mar 14, 2019 5:55 am

BTGmoderatorDC wrote:Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900

OA A

Source: Princeton Review

The total loss of all the friends is 500 dollars. Since two friends lost 380 dollars, the remaining 3 friends lost a total of 120 dollars, or an average of 120/3 = 40 dollars.

Answer: A

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