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Find the fourth consecutive even number 1) The sum of the

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by subh2273 » Mon Oct 08, 2018 9:50 pm
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Find the fourth consecutive even number

1) The sum of the last two numbers is 30
2) The sum of the first two numbers is 22
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Source: — Problem Solving |

by Jay@ManhattanReview » Tue Oct 09, 2018 4:21 am
subh2273 wrote:Find the fourth consecutive even number

1) The sum of the last two numbers is 30
2) The sum of the first two numbers is 22
What's the source of the question? It's a poorly-worded question.

Let's take each statement one by one.

1) The sum of the last two numbers is 30.

Say the four even consecutive numbers are n, (n + 2), (n + 4), and (n + 6).

Thus, as per the information (n + 4) + (n + 6) = 2n + 10 = 30 => n = 10

Thus, the 4th even consecutive number = n + 6 = 10 + 6 = 16. Sufficient.

2) The sum of the first two numbers is 22.

Say the four even consecutive numbers are n, (n + 2), (n + 4), and (n + 6).

Thus, as per the information n + (n + 2) = 2n + 2 = 22 => n = 10

Thus, the 4th even consecutive number = n + 6 = 10 + 6 = 16. Sufficient.

The correct answer: D

Hope this helps!

-Jay
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by Jay@ManhattanReview » Tue Oct 09, 2018 4:21 am
subh2273 wrote:Find the fourth consecutive even number

1) The sum of the last two numbers is 30
2) The sum of the first two numbers is 22
What's the source of the question? It's a poorly-worded question.

Let's take each statement one by one.

1) The sum of the last two numbers is 30.

Say the four even consecutive numbers are n, (n + 2), (n + 4), and (n + 6).

Thus, as per the information (n + 4) + (n + 6) = 2n + 10 = 30 => n = 10

Thus, the 4th even consecutive number = n + 6 = 10 + 6 = 16. Sufficient.

2) The sum of the first two numbers is 22.

Say the four even consecutive numbers are n, (n + 2), (n + 4), and (n + 6).

Thus, as per the information n + (n + 2) = 2n + 2 = 22 => n = 10

Thus, the 4th even consecutive number = n + 6 = 10 + 6 = 16. Sufficient.

The correct answer: D

Hope this helps!

-Jay
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Locations: New York | Bangkok | Abu Dhabi | Rome | and many more...

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Join the discussion