factors

i would say 25..

36^2 cab be written as 3^4* 2^4

hence the number of factors are (4+1) * (4+1) = 25..

let me know the OA.

i understand this: 36^2 cab be written as 3^4* 2^4

but how do you go from there and arrive at the answer 25???

I have the same question as Dago. Thanks

There is rule to find the factors of any integer.

Suppose you need to find the number of factors for 20

First prime factorize

20 = 2*2*5 = 2^2 * 5^1

now just look at the exponents of two prime factors, you add 1 to each power and then multiply with each other

(2+1)*(1+1) = 3*2= 6

20 has 6 factors

1,2,4,5,10,20.

Similarly for 36^2 = 2^4 * 3^4

(4+1)*(4+1) = 5*5 =25

Hope its clear now.

Thank you. Makes sense now.

parallel_chase wrote:There is rule to find the factors of any integer.

Suppose you need to find the number of factors for 20

First prime factorize

20 = 2*2*5 = 2^2 * 5^1

now just look at the exponents of two prime factors, you add 1 to each power and then multiply with each other

(2+1)*(1+1) = 3*2= 6

20 has 6 factors

1,2,4,5,10,20.

Similarly for 36^2 = 2^4 * 3^4

(4+1)*(4+1) = 5*5 =25

Hope its clear now.

Great trick-thanks for that! Is there a similar trick if it were to ask for prime factors only?