BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

factorial problem

Expert replies
by gmat009 » Mon Nov 17, 2008 10:15 am
I am not sure if this question has been discussed before.
I tried to search it but couldn't find.


Can someone explain me what this question is really asking for.
What exactly do we need to prove.
Attachments
Doc1.doc
(74.5 KiB) Downloaded 140 times
Join the discussion
Source: — Data Sufficiency |

by cramya » Mon Nov 17, 2008 3:10 pm
Its basically asking if k is prime or not. If k were prime then 1 and k would be the only factors and there would be no p a factor of k such that
1<p<k

Stmt I

k>4!
4!=24

If k=25 the answer is yes
If k = 29 the answer is no

INSUFF

Stmt II

13!+2<=k<=13!+13

Any number between 13!+2 and 13!+13 will always be non prime i.e they will have factors from 2-13 (write out 13! = 13*12*11*10*9*8*7*6*5*4*3*2*1 )

Once a number is divisible by 2,3,4...if u keep adding 2 or 3 or 4... it will always be divisible by it again

This tell us k is non prime and 1<p<k exists

B)

Hope this helps! Let me know if u still have questions
Join the discussion