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factor problem

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by simba12123 » Mon Nov 03, 2008 8:14 pm
If 5^(6x) = 125,000 Then, 5^(2x−1) = ?

5^6x= 5^3 10^3

(5^6x) - (5^3) =10^3

so ((5^6x) - (5^3))/3 = 10^3/3

I think i am on the right track and need to tie this up!



qa 10

Source is GuruGuide and its an advanced question.
Last edited by simba12123 on Mon Nov 03, 2008 8:33 pm, edited 3 times in total.
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Source: — Problem Solving |
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by cramya » Mon Nov 03, 2008 8:23 pm
Can u please chekc the problem again?

I am not able to understand how 5 ^ any power value be 10

Whats the source?
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Re: factor problem

by stubbornp » Mon Nov 03, 2008 9:14 pm
simba12123 wrote:If 5^(6x) = 125,000 Then, 5^(2x−1) = ?

5^6x= 5^3 10^3

(5^6x) - (5^3) =10^3

so ((5^6x) - (5^3))/3 = 10^3/3

I think i am on the right track and need to tie this up!



qa 10



Source is GuruGuide and its an advanced question.
5^6x= 5^3 10^3

(5^6x)/5^3=10^3

5^(6x-3)=10^3

5^(2x-1)3=10^3

taking cube root both sides

5^(2x-1)=10...hope it clears
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by cramya » Mon Nov 03, 2008 11:19 pm
Nice work stubbornp!

5^(6x-3)=10^3 Got up to here and dint have an answer after that for Simba

When u did 5 ^ ((2x-1) * 3)) are u doing a^(b*c) = (a^b) ^ c to get to

(5 ^ (2x-1)) ^ 3 i.e where a=5 b = 2x-1 c=3

Let me know!
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by raunekk » Mon Nov 03, 2008 11:38 pm
5^6x= 5^3 10^3

(5^6x)/5^3=10^3

5^(6x-3)=10^3

5^(2x-1)3=10^3

taking cube root both sides

5^(2x-1)=10...hope it clears

perfect explanation

imo:10
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by raunekk » Mon Nov 03, 2008 11:44 pm
Nice work stubbornp!

5^(6x-3)=10^3 Got up to here and dint have an answer after that for Simba

When u did 5 ^ ((2x-1) * 3)) are u doing a^(b*c) = (a^b) ^ c to get to

(5 ^ (2x-1)) ^ 3 i.e where a=5 b = 2x-1 c=3

u can write 5 ^ ((2x-1) * 3)) as 5^ 3 * ((2x-1))..

and cube root of 5^ 3*(2x-1) = 5 ^ 2x-1

i hope it helps...
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by Hope700 » Tue Nov 04, 2008 9:02 am
Simply Marvelous Stubbornp
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Re: factor problem

by logitech » Tue Nov 04, 2008 9:09 am
simba12123 wrote:If 5^(6x) = 125,000 Then, 5^(2x−1) = ?

5^6x= 5^3 10^3

(5^6x) - (5^3) =10^3

so ((5^6x) - (5^3))/3 = 10^3/3

I think i am on the right track and need to tie this up!



qa 10

Source is GuruGuide and its an advanced question.
5^(2x−1), simply means: 5^2x/5

So we should hunt for 5^2x

since If 5^(6x) = 125,000 = 5^3 10^3 ( EASY TO SPOT )

5^2x = 5 x 10 :idea:

Therefore, 5^2x/5 = 10

Another way to think a problem is always good!
LGTCH
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