*Please post in the right designated forum*


IMO A

Use strategy of picking numbers,

If you pick 4 as n,

then h(4) + 1 = 9 which makes 3 the only prime factor

Since the function is true for all n, the answer must be A, as its the only answer choice whose range includes 3.

Hence A

The question is specifically asking for factor of h(100)+1. It is not asking for factor of all h(n)+1.

Sorry about posting in the wrong area. I am new to this.

Anindya Madhudor wrote:The question is specifically asking for factor of h(100)+1. It is not asking for factor of all h(n)+1.

Yes, I misread the question and stand corrected.

By taking 2 as common, we can rewrite h(100) as

2^50x(1x2x3x...x50).

Hence every number from 1 to 50 is a factor of 100

So every h(100) + 1 will not be a factor and will leave remainder as one (including primes).

Hence the smallest prime will be above 50.

Answer E seems to fit the description.

Hence E

P.S. Whats the source of the question.

It came up in one of the two sample tests provided by official GMAC.