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by Stuart@KaplanGMAT » Mon Nov 23, 2009 6:09 pm
heshamelaziry wrote:What is the units' digit of 9^5 * 13^3 * 7^3 ?

[spoiler]OA 9. I don't like kaplan approach. Appreciate any help.[/spoiler]
Don't like Kaplan approach! Blasphemy!

I haven't looked at the official explanation (hard to believe, but I haven't memorized every Kaplan question), but we can solve fairly quickly by focusing on patterns of units digits.

9^1 = 9
9^2 = 81
9^3 = ..9
9^4 = ..1
9^5 = ..9

13^1 = ...3
13^2 = ... 9
13^3 = ...7

7^1 = 7
7^2 = ...9
7^3 = ...3

So, we have (...9)(...7)(...3) = (...3)(...3) = ...9
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by aspirant1 » Mon Nov 23, 2009 9:16 pm
Stuart, Great explanation and method , Thanks
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