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Exponents

Expert replies
by heshamelaziry » Mon Sep 21, 2009 3:33 pm
The value of (2^-14 + 2^-15 + 2^-16 + 2^-17)/5 is how many times the value of 2^-17 ?

The answer seems to have a flaw in multiplying fractions !!!
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Source: — Problem Solving |

Re: Exponents

by Brent@GMATPrepNow » Mon Sep 21, 2009 6:00 pm
heshamelaziry wrote:The value of (2^-14 + 2^-15 + 2^-16 + 2^-17)/5 is how many times the value of 2^-17 ?

The answer seems to have a flaw in multiplying fractions !!!
For some reason, I'm having a hard time adding an image to the post. So, I've attached the solution.

Cheers,
Brent
You do not have the required permissions to view the files attached to this post.
Brent Hanneson - Creator of GMATPrepNow.com
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Re: Exponents

by heshamelaziry » Mon Sep 21, 2009 6:11 pm
Brent Hanneson wrote:
heshamelaziry wrote:The value of (2^-14 + 2^-15 + 2^-16 + 2^-17)/5 is how many times the value of 2^-17 ?

The answer seems to have a flaw in multiplying fractions !!!
For some reason, I'm having a hard time adding an image to the post. So, I've attached the solution.

Cheers,
Brent
it shuold be ((2^-14 + 2^-15 + 2^-16 + 2^-17)/5 )/ 2^-17 which translates to:

((2^-14 + 2^-15 + 2^-16 + 2^-17)/5 * 1/ 2^-17.

I don't know what i am missing ! i.e (2/5)/4 = 2/5 * 1/4. Shouldn't it be the same principal ?
Join the discussion

Re: Exponents

by Brent@GMATPrepNow » Mon Sep 21, 2009 6:19 pm
heshamelaziry wrote:
Brent Hanneson wrote:
heshamelaziry wrote:The value of (2^-14 + 2^-15 + 2^-16 + 2^-17)/5 is how many times the value of 2^-17 ?

The answer seems to have a flaw in multiplying fractions !!!
For some reason, I'm having a hard time adding an image to the post. So, I've attached the solution.

Cheers,
Brent
it shuold be ((2^-14 + 2^-15 + 2^-16 + 2^-17)/5 )/ 2^-17 which translates to:

((2^-14 + 2^-15 + 2^-16 + 2^-17)/5 * 1/ 2^-17.

I don't know what i am missing ! i.e (2/5)/4 = 2/5 * 1/4. Shouldn't it be the same principal ?
It's probably easier to rewrite ((2^-14 + 2^-15 + 2^-16 + 2^-17)/5 )/ 2^-17 as ((2^-14 + 2^-15 + 2^-16 + 2^-17)/5 ) x 2^17

Then you get: (2^3 + 2^2 + 2^1 + 1)/5 = 3

Useful rule here: 1/(x^-n) = x^n
Brent Hanneson - Creator of GMATPrepNow.com
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