BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

exponents are killing me

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 10
Joined: Tue Jul 22, 2008 6:57 pm
by Wakka Wakka » Thu Jul 24, 2008 10:41 am
From a question in the MH GMAT practice test...from step 1 to step 2 we loose 5^13 which becomes (5-1)...can someone explane this to me please? THanks


1.) 5^12 – 6(5^13 – 5^12) =
2.) 5^12 – 6[5^12(5 – 1)] =
3.) 5^12 – 6(5^12)(4) =
4.) 5^12(1 – 24) =
5.) (-23)5^12.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 10
Joined: Tue Jul 22, 2008 6:57 pm

by Wakka Wakka » Thu Jul 24, 2008 10:45 am
I guess it couldn't hurt to post the question also...

A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^13, respectively, what is the value of A?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times

by sudhir3127 » Thu Jul 24, 2008 10:47 am
5^12 – 6(5^13 – 5^12)

5^13 canbe written as 5^12*5 ( as the bases are same powers can be added)

hence it will be 5^12- 6( 5^12*5- 5^12)
5^12- 6.5^12( 5-1)
5^12 – 6(5^12)(4)

5^12(1 – 24)

hope its clear now.. let meknow if u still have a doubt..
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 10
Joined: Tue Jul 22, 2008 6:57 pm

by Wakka Wakka » Thu Jul 24, 2008 10:56 am
I really appreciate it thank you...also thank for the quick reply.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 10
Joined: Tue Jul 22, 2008 6:57 pm

by Wakka Wakka » Thu Jul 24, 2008 1:05 pm
I was just going over the formula and I get that we can take 5^13 to 5^12*5, but how do we get one 5^12 to become 1?

Thanks
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 10
Joined: Tue Jul 22, 2008 6:57 pm

by Wakka Wakka » Thu Jul 24, 2008 2:10 pm
Nevermind...haha, just saw it...really appreciate it though, THANKS!!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1