BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Exponent values-GMATPREPI

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times

Re: Exponent values-GMATPREPI

by sudhir3127 » Mon Aug 18, 2008 8:05 pm
medea66 wrote:How do you solve for this?
i am sure the question shud read like this ...

2^(x + Y)^2)/2^(x - Y)^2 ...

anyways here we go

2^((x+y)^2 - (x-y)^2)

2^(x^2 + 2xy + y^2 - x^2 + 2xy - y^2)

2^(4xy)

2^4*1 = 16..

hope this helps.. i am sure after u see the question in the right way ..its not at all difficult
Last edited by sudhir3127 on Mon Aug 18, 2008 8:37 pm, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 69
Joined: Fri Jul 11, 2008 8:49 am
Thanked: 1 times

Re: Exponent values-GMATPREPI

by uncbeers » Mon Aug 18, 2008 8:23 pm
sudhir3127 wrote:
medea66 wrote:How do you solve for this?
i am sure the question shud read like this ...

2^(x + Y)^2)/2^(x - Y)^2 ... GMAT PREP we dont except this!!!!!!

anyways here we go

2^((x+y)^2 - (x-y)^2)

2^(x^2 + 2xy + y^2 - x^2 + 2xy - y^2)

2^(4xy)

2^4*1 = 16..

hope this helps.. i am sure after u see the question in the right way ..its not at all difficult
What is different from the problem in GMATPrep and the way you wrote it? I think it is the corrected form of the problem.

Also, shouldn't that second 2xy be a -2xy in [2^(x^2 + 2xy + y^2 - x^2 + 2xy - y^2) ]? That way it is 2^ (2xy - (-2xy)) to become 2^(4xy)?

(x+y)^2 = x^2 + 2xy + y^2
(x-y)^2 = x^2 -2xy + y^2


Hope that is right...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times

Re: Exponent values-GMATPREPI

by sudhir3127 » Mon Aug 18, 2008 8:39 pm
uncbeers wrote:
sudhir3127 wrote:
medea66 wrote:How do you solve for this?
i am sure the question shud read like this ...

2^(x + Y)^2)/2^(x - Y)^2 ...

anyways here we go

2^((x+y)^2 - (x-y)^2)

2^(x^2 + 2xy + y^2 - x^2 + 2xy - y^2)

2^(4xy)

2^4*1 = 16..

hope this helps.. i am sure after u see the question in the right way ..its not at all difficult
What is different from the problem in GMATPrep and the way you wrote it? I think it is the corrected form of the problem.

Also, shouldn't that second 2xy be a -2xy in [2^(x^2 + 2xy + y^2 - x^2 + 2xy - y^2) ]? That way it is 2^ (2xy - (-2xy)) to become 2^(4xy)?

(x+y)^2 = x^2 + 2xy + y^2
(x-y)^2 = x^2 -2xy + y^2


Hope that is right...
ur right on 2xy -(-2xy) .. If u see i have already factored in that step and done the calculation...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 186
Joined: Sat Jan 26, 2008 10:05 pm
Thanked: 2 times

by medea66 » Wed Aug 20, 2008 5:56 pm
So how do you get 2^4*1 = 16 from 2^(4xy)? Where does the 1 come from?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 661
Joined: Tue Jul 08, 2008 12:58 pm
Location: France
Thanked: 48 times

by pepeprepa » Thu Aug 21, 2008 1:49 am
xy=1 comes from the question :wink:
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 186
Joined: Sat Jan 26, 2008 10:05 pm
Thanked: 2 times

by medea66 » Thu Aug 21, 2008 5:33 pm
Oh, duh, that was a stupid question on my part.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1