Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

exponent and radical simplification

Expert replies
by Lakers09 » Mon Nov 03, 2008 7:29 pm
Hi All,
I am having trouble attacking this problem. For starters, how do I know that it is a 45-45-90 triagle by the information given? in the first part of the explanation how do they arrive at xrad3

Any help would be great.

Thanks
You do not have the required permissions to view the files attached to this post.
Join the discussion
Source: — Problem Solving |

by stubbornp » Mon Nov 03, 2008 10:24 pm
let the side of cube be x...ac=x

distance of bc=(3^0.5)x=1.732x

distance of ab=(2^0.5)x=1.414x

difference=1.732x-1.414x=0.318x~==0.3x

0.3x is 30% of x.....hope it clears
Join the discussion

by Lakers09 » Mon Nov 03, 2008 10:42 pm
Thanks so much for your response

how did you arrive at bc=(3^0.5)x and ab=(2^0.5)x ???



distance of bc=(3^0.5)x=1.732x

distance of ab=(2^0.5)x=1.414x


Thanks
Join the discussion

by raunekk » Mon Nov 03, 2008 11:15 pm
using pythagoras theorem..
u will b able to find line segment BC
and similarly AB
Let AC=x

Thus BC=root of( x^2 + x^2 ) + x^2 = x root3=1.732x
AB= root of( x^2 + x^2 ) = x root2=1.414x

Thus BC- AB = 0.318x

i.e 0.318x/ x * 100 = 30% (approx.)
Join the discussion

by Lakers09 » Tue Nov 04, 2008 11:11 am
I feel like an idiot. I understand pythag theorem. Maybe I am forgetting some rules about simplifying radicals and exponents? any suiggestions?
Join the discussion

by elmiko » Tue Nov 04, 2008 3:23 pm
raunekk wrote:
Thus BC=root of( x^2 + x^2 ) + x^2 = x root3=1.732x
AB= root of( x^2 + x^2 ) = x root2=1.414x
I must have forgotten this rule of roots/exponents.

What is/are the rule/s for taking the square root of numbers with exponents?

I know that the general rule in simplifying the z'th root of (x^n) = x^n/z.
i.e. cubed root (x^2) = x^2/3.

How do you simplify when there is more than 1 term within a square root?
Join the discussion

by kanishkporwal » Fri Sep 16, 2011 10:00 pm
Lakers09 wrote:I feel like an idiot. I understand pythag theorem. Maybe I am forgetting some rules about simplifying radicals and exponents? any suiggestions?
If you are forgetting the basics on radical simplification then you should definitely check this link

https://math.tutorvista.com/number-syste ... icals.html
Join the discussion