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Explanation for DS question

Expert replies
by nadib002 » Wed Mar 31, 2010 10:42 pm
Is p divisible by 168?

(1) p is divisible by 14
(2) p is divisible by 12

Could someone please explain an approach to answer this DS question without substituting numbers?

Thank you


P.S. I am not adding the answer choices since they are same for all the DS questions.
Join the discussion
Source: — Data Sufficiency |

by gmatmachoman » Wed Mar 31, 2010 10:50 pm
nadib002 wrote:Is p divisible by 168?

(1) p is divisible by 14
(2) p is divisible by 12

Could someone please explain an approach to answer this DS question without substituting numbers?

Thank you


P.S. I am not adding the answer choices since they are same for all the DS questions.
step 1: Find the factors of 168 ---->( 2 ,3,7)

Using St 1:

Factors of 14 :( 2,7)

What if the P is a multiple of 3???. SO factors of 14 won't divide P --St 1 is insufficient

Using st 2:

factors of 12 : (2,3)
What if p is a multiple of 7?? So factors of 12 wont divide P--St 2 is insufficient

Combining St1 & St2:
U an divide P as all three factors are included in the set!!

So C
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by ajith » Wed Mar 31, 2010 11:06 pm
nadib002 wrote:Is p divisible by 168?

(1) p is divisible by 14
(2) p is divisible by 12

Could someone please explain an approach to answer this DS question without substituting numbers?

Thank you


P.S. I am not adding the answer choices since they are same for all the DS questions.
Any number which has factors 4,3 and 7 will be divisible by 14 and 12

84 is smallest of such numbers and it is not divisible by 168

Hence E
Always borrow money from a pessimist, he doesn't expect to be paid back.
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by gmatmachoman » Wed Mar 31, 2010 11:57 pm
@Ajith

If the question would have been : Is P divisible by 84??

Hope Both statements together will wrk rite??
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by eaakbari » Thu Apr 01, 2010 1:02 am
Stem
168 = 2^3 * 7 *3

Hence p will have to have all of the following factors to be divisible by 168

Statement one
14 = 2 * 7
Hence p is div by 2 and 7
But insuff

Statemnent two
2^2 * 3
Hnce p is div by 2^2 and 3
Insuff

Combining
we can say p is div by 2^2 and 3 and 7
But we need another factor of 2 to be div by 168

Hence insuff

Answer E
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by ajith » Thu Apr 01, 2010 1:42 am
gmatmachoman wrote:@Ajith

If the question would have been : Is P divisible by 84??

Hope Both statements together will wrk rite??
Yes it would have worked!

84 is the LCM of 12 and 14!
Always borrow money from a pessimist, he doesn't expect to be paid back.
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by anoopprasad » Sat Apr 03, 2010 11:12 pm
168 = 14 * 12
So if p is divisible by 14 and 12 it is divisible by 188

Ans: C
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by ajith » Sat Apr 03, 2010 11:36 pm
anoopprasad wrote:168 = 14 * 12
So if p is divisible by 14 and 12 it is divisible by 188

Ans: C
what about 84?

or 252
Always borrow money from a pessimist, he doesn't expect to be paid back.
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by thephoenix » Sun Apr 04, 2010 12:05 am
ans is E
clearly s1 and 2 are not suff
lcm of 12 and 14 is 84
combining bth minimum posssible no is 84 which is not div by 168 and rest all are
hence no conclusion and therefore insuff
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