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Problem Solving — algebra and arithmetic
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by AJWILL » Sun Jul 22, 2012 3:17 am
In how many ways can we put 4 different balls in 3 different boxes when any box can contain any number of balls?

[A] 80
81
[C] 64
[D] 63
[E] 82
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by eagleeye » Sun Jul 22, 2012 8:52 am
AJWILL wrote:In how many ways can we put 4 different balls in 3 different boxes when any box can contain any number of balls?

[A] 80
81
[C] 64
[D] 63
[E] 82


Each of the 4 balls has the option of going into any of the 3 bins.
Total number of ways = (options for ball 1)*(options for ball2)*(for ball3)*(for ball4)
= 3*3*3*3 = 3^4 = 81.

Cheers :)
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