EXPERTS PLEASE HELP

AJWILL wrote:In compny x the median annual salary is $50000. what percent of the employees earned less than $80000 and more than $50,000?
1)the employees who earned less than $80,000 and more than $50,000 is equal to the number of the employees who earned no less than $80,000
2)30% of the total salary was earned by the employees who earned less than $80000 and more than $50000

We are asked to find % of employees... which means no. of employees/ total number of employees

Glancing through the choices, I do not see any number of employees given, so the question cannot be answered. Also no infomation is given about employees with salaries under 50,000

First thing is that wording here is pretty poor.

Second

Statement 1 says that the number of people between 50k and 80k is equal to the number above 80k
Statement 2 says that the total dollar figure earned by people earning between 50k and 80k is 30% of the total dollar amount.

The answer is E because we have no idea the income distribution.

I think the answer is A. We need to solve for (50K < Num < 80K)/N, where N is the total number of employees, and Num is the number of employees that earn between 50K and 80K.

Since the median is 50K, half earn less/eq than 50K, half earn more/eq than 50K, so there are N/2 employees that earn above 50K. Statement #1 tells us that the number above 80K equals that between 50K and 80K, so we know that between 50K and 80K we have N/4. Therefore, the answer is 1/4, and #1 is sufficient. #2 isn't sufficient - it gives no info on the number. Thus, the answer is A.

piti wrote:I think the answer is A. We need to solve for (50K < Num < 80K)/N, where N is the total number of employees, and Num is the number of employees that earn between 50K and 80K.

Since the median is 50K, half earn less/eq than 50K, half earn more/eq than 50K, so there are N/2 employees that earn above 50K. Statement #1 tells us that the number above 80K equals that between 50K and 80K, so we know that between 50K and 80K we have N/4. Therefore, the answer is 1/4, and #1 is sufficient. #2 isn't sufficient - it gives no info on the number. Thus, the answer is A.

We need to find the percentage of employees who earned less than $80000 and more than $50,000?
If we don't know the total number of employees we can't solve this problem!
We don't even know the highest salary or the lowest salary!

In compny x the median annual salary is $50000. what percent of the employees earned less than $80000 and more than $50,000?
1)the employees who earned less than $80,000 and more than $50,000 is equal to the number of the employees who earned no less than $80,000
What if there were employees who earned over 80,000?


2)30% of the total salary was earned by the employees who earned less than $80000 and more than $50000
What if there were employees who earned over 80,000?

Hope I am right

The wording is indeed rather slack. But it's just possible to infer C as the answer, as follows:

1) tells us that employees earning more than the median can be split equally into those earning >80k and those earning <=80k. Since 50% earn more than the median, it appears that 25% earn between 50k and 80k. Looking good... BUT! If everyone earned exactly 50k, all these conditions are satisfied with no-one earning >50k-80k. So because of the edge case, this is INSUFFICIENT.

2) on its own, this is INSUFFICIENT, because knowing the total salary fraction of this 50-80k group does not tell us how many there are.

However, statement 2 does rule out the edge case in statement 1 -- i.e. taking the statements together, we know some employees earn >50k. Hence the answer is C.[/spoiler]