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Equations

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Source: — Data Sufficiency |
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by Naruto » Wed Aug 26, 2009 10:12 pm
IMO D

Each alone is sufficient,
the equation is of form a^2-b^2, i.e (a+b) x (a-b)

if a+b is given we can find value of a-b and then solving the two the value of a

Same goes for a-b.
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by niraj_a » Wed Aug 26, 2009 10:38 pm
i see naruto. here's my question though -

say in 1) we arbitrarily square the whole string, so we get

x^2/9 + 4/y^2 = 36

so we add the stem and this result to get

2(x^2/9) = 36
(x^2) = 2
so x = + or - 1.41

the same issue happens if you square statement 2. where did i go wrong? it doesnt say anywhere is x or y are integers or -ve.
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by KK9_GMAT » Thu Aug 27, 2009 1:39 am
niraj_a,

When you square 1) ie. (x/3 + 2/y)^2 = 6^2,
using (a+b)^2 = a^2 + 2ab + b^2

we get, (x^2/9) + 2((x/3)*(2/y)) + (4/y^2) = 36
(x^2/9) + (4x/3y) + (4/y^2) = 36

which is not equal to what you calculated.
I think this is where you might have gone wrong.
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by niraj_a » Thu Aug 27, 2009 4:27 am
kudos, thanks much.

i guess i'll never score high on the quant....
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by KK9_GMAT » Thu Aug 27, 2009 6:19 am
No worries. Better to commit mistakes now than in the actual exam. :)
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Re: Equations

by vikram_k51 » Thu Aug 27, 2009 11:48 pm
niraj_a wrote:If x^2/9 - 4/y^2 = 12, what is the value of x?

(1) x/3 + 2/y = 6

(2) x/3 - 2/y = 2

Those blobs stand for negative
Answer will be D.
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Re: Equations

by fruti_yum » Tue Sep 01, 2009 10:10 am
vikram_k51 wrote:
niraj_a wrote:If x^2/9 - 4/y^2 = 12, what is the value of x?

(1) x/3 + 2/y = 6

(2) x/3 - 2/y = 2

Those blobs stand for negative
Answer will be D.
When i solve each of the statements , i get either y = 6 or x = 12 for both individually..

Where do i go from there in the question stem?
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