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Equations

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by welcome » Thu Jan 08, 2009 10:45 am
4+x = 1 => x=-3 ----2nd Row
e+x=5 => e+(-3)=5 => e=8 ----3rd Row
e+z=10=> 8+z=10 => z=2 ---3rd Row

4+z=m => 4+2 =6=z. ---1st Row

Oooop Forgot n :(.

4+y= -5 => y = -9.

e+y =n => n => -1

so m+n = 6-1 = 5.

Answer is 5.
Last edited by welcome on Thu Jan 08, 2009 12:01 pm, edited 1 time in total.
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Re: Equations

by logitech » Thu Jan 08, 2009 11:11 am
m+n = (4+z) +(e+y) Little trick! - Re-arrange
= (4+y) + (e+Z)
= (-5) + ( 10)
= 5
LGTCH
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Re: Equations

by shobha.r.iyer » Thu Jan 08, 2009 11:14 am
logitech wrote:m+n = (4+z) +(e+y) Little trick! - Re-arrange
= (4+y) + (e+Z)
= (-5) + ( 10)
= 5
Hi Logitech

could not understand the rearrangement
can you please explain in some details...
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Re: Equations

by shobha.r.iyer » Thu Jan 08, 2009 11:15 am
logitech wrote:m+n = (4+z) +(e+y) Little trick! - Re-arrange
= (4+y) + (e+Z)
= (-5) + ( 10)
= 5
The answer 5 is right
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Re: Equations

by logitech » Thu Jan 08, 2009 11:18 am
shobha.r.iyer wrote:
logitech wrote:m+n = (4+z) +(e+y) Little trick! - Re-arrange
= (4+y) + (e+Z)
= (-5) + ( 10)
= 5
The answer 5 is right
a+b+c+d = a+d+b+c

we know what m+n is equal to:

4+z+e+y

so try to find in the table whether you can use any of the pairs, since

4+y is defined as -5 use it
and since you are left with e+z use it too.

The guy who designed this question wanted us to see this so it is not a coincidence . If you see a question like that in the future you will understand what I mean.
LGTCH
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Re: Equations

by shobha.r.iyer » Thu Jan 08, 2009 11:21 am
logitech wrote:
shobha.r.iyer wrote:
logitech wrote:m+n = (4+z) +(e+y) Little trick! - Re-arrange
= (4+y) + (e+Z)
= (-5) + ( 10)
= 5
The answer 5 is right
a+b+c+d = a+d+b+c

we know what m+n is equal to:

4+z+e+y

so try to find in the table whether you can use any of the pairs, since

4+y is defined as -5 use it
and since you are left with e+z use it too.

The guy who designed this question wanted us to see this so it is not a coincidence . If you see a question like that in the future you will understand what I mean.
thanks logitech
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Re: Equations

by shobha.r.iyer » Thu Jan 08, 2009 12:38 pm
shobha.r.iyer wrote:
logitech wrote:
shobha.r.iyer wrote:
logitech wrote:m+n = (4+z) +(e+y) Little trick! - Re-arrange
= (4+y) + (e+Z)
= (-5) + ( 10)
= 5
The answer 5 is right
a+b+c+d = a+d+b+c

we know what m+n is equal to:

4+z+e+y

so try to find in the table whether you can use any of the pairs, since

4+y is defined as -5 use it
and since you are left with e+z use it too.

The guy who designed this question wanted us to see this so it is not a coincidence . If you see a question like that in the future you will understand what I mean.
thanks logitech
i was solving this question as three equations with 4 variables
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Re: Equations

by kanha81 » Sat Jan 10, 2009 10:18 pm
logitech wrote:m+n = (4+z) +(e+y) Little trick! - Re-arrange
= (4+y) + (e+Z)
= (-5) + ( 10)
= 5
Brilliant! Thanks.
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