If x = 0 and x = sqrt(8xy-16y^2) , then, in terms of y, x = ?
A. - 4y
B. y/4
C. y
D. 4y
E. 4y^2
OA D
A. - 4y
B. y/4
C. y
D. 4y
E. 4y^2
OA D
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We can take 8 x y - 16 y^2 = 0 or 8 x y = 16 y^2 , but if x is already 0, y should also be 0 to hold the stem as true, and in that case, division by either x or y is not valid, and the question cannot be answered. I am not convinced with the contents supplied to work on, it's making me limcakumarthumsup, huh!colakumarfanta wrote:If x = 0 and x = sqrt(8xy-16y^2) , then, in terms of y, x = ?
A. - 4y
B. y/4
C. y
D. 4y
E. 4y^2
OA D
And if x ≠0, then x^2 = 8 x y - 16 y^2sanju09 wrote:We can take 8 x y - 16 y^2 = 0 or 8 x y = 16 y^2 , but if x is already 0, y should also be 0 to hold the stem as true, and in that case, division by either x or y is not valid, and the question cannot be answered. I am not convinced with the contents supplied to work on, it's making me limcakumarthumsup, huh!colakumarfanta wrote:If x = 0 and x = sqrt(8xy-16y^2) , then, in terms of y, x = ?
A. - 4y
B. y/4
C. y
D. 4y
E. 4y^2
OA D
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