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Source: — Problem Solving |
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by theCodeToGMAT » Sun Nov 03, 2013 6:07 am
Price = 2 + 5/[sqrt(3-x)]

x>0 & x<3

Price = 9

9 = 2 + 5/[sqrt(3-x)]

7 = 5/[sqrt(3-x)]

[sqrt(3-x)] = 5/7

squaring

3-x = 25/49

x = 3 - 25/49 => 3 - ~.5 = 2.5

Answer {D}
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by [email protected] » Sun Nov 03, 2013 7:00 am
Need to understand the question being asked here, before understanding the process to solve!


[email protected] wrote:Dint get the question :(
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by Brent@GMATPrepNow » Sun Nov 03, 2013 7:41 am
[email protected] wrote:Need to understand the question being asked here, before understanding the process to solve!
The cost of 1 hour's worth of electricity depends on how many kilowatts of electricity were used.
x = the number kilowatts of electricity used

The cost of 1 hour of electricity = 2 + 5/√(3-x)
So, for example, if we use 2 kilowatts, x = 2, then . . .
the cost of 1 hour of electricity = 2 + 5/√(3-2)
= 2 + 5/√1
= 7 (dollars)

The question tells us that the cost of 1 hour of electricity = $9.00
So, we can write: 9 = 2 + 5/√(3-x) [we must solve for x]
Subtract 2 from both sides: 7 = 5/√(3-x)
Multiply both sides by √(3-x) to get: 7√(3-x) = 5
Divide by 7 to get: √(3-x) = 5/7
Square both sides to get: 3-x = 25/49
Solve for x: x = 3 - 25/49
Since 25/49 ≈ 0.5, we can see that x ≈ 3 - 0.5 ≈ 2.5

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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