Eight friends go to watch a movie but only 5 tickets were

Eight friends go to watch a movie but only 5 tickets were available. In how many different ways can 5 people sit and watch the movie?

A. 8C5
B. 8*7*6*5*4
C. 5!
D. $\frac{8!}{5!}$
E. 8*5

The OA is B

Source: Veritas Prep

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by Scott@TargetTestPrep » Wed May 29, 2019 5:54 pm

swerve wrote:Eight friends go to watch a movie but only 5 tickets were available. In how many different ways can 5 people sit and watch the movie?

A. 8C5
B. 8*7*6*5*4
C. 5!
D. $\frac{8!}{5!}$
E. 8*5

The OA is B

Source: Veritas Prep

The number of ways 5 people can sit (order matters) and watch the movie is 8P5 = 8 x 7 x 6 x 5 x 4.

Answer: B

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