Eddy and Freddy start simultaneously from city $A$ and they travel to City $B$ and City $C$ respectively. Eddy tak

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Vincen: Legendary Member; Posts: 2898; Joined: Thu Sep 07, 2017 2:49 pmFollowed by: 5 members; Thanked: 6 times

by Vincen » Tue Oct 06, 2020 7:03 am

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Eddy and Freddy start simultaneously from city $A$ and they travel to City $B$ and City $C$ respectively. Eddy takes $3$ hours and Freddy takes $4$ hours to complete the journey. If the distance between City $A$ and City $B$ is $600 \, \text{km}$ and City $A$ and City $C$ is $300 \, \text{km}.$ What is the ratio of their average speed of travel? (Eddy: Freddy)

A. $\dfrac83$

B. $\dfrac38$

C. $\dfrac85$

D. $\dfrac58$

E. $\dfrac53$

Answer: A

Source: GMAT Club Tests

Source: Beat The GMAT — Problem Solving | Tue Oct 06, 2020 7:03 am

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Re: Eddy and Freddy start simultaneously from city $A$ and they travel to City $B$ and City $C$ respectively. Eddy

by Scott@TargetTestPrep » Sat Oct 10, 2020 2:32 pm

Vincen wrote: ↑
Tue Oct 06, 2020 7:03 am
Eddy and Freddy start simultaneously from city $A$ and they travel to City $B$ and City $C$ respectively. Eddy takes $3$ hours and Freddy takes $4$ hours to complete the journey. If the distance between City $A$ and City $B$ is $600 \, \text{km}$ and City $A$ and City $C$ is $300 \, \text{km}.$ What is the ratio of their average speed of travel? (Eddy: Freddy)

A. $\dfrac83$

B. $\dfrac38$

C. $\dfrac85$

D. $\dfrac58$

E. $\dfrac53$

Answer: A

Source: GMAT Club Tests

Solution:

Eddie’s average speed is 600/3 = 200 km/hr. Freddy’s average speed is 300/4 = 75 km/hr. Therefore, the ratio of Eddy’s average speed to that of Freddy is 200/75 = 8/3.

Answer: A

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