Each week a restaurant serving Mexican food uses the same volume of chili paste, which comes in either 25-ounce cans or 15-ounce cans of chili paste. If the restaurant must order 40 more of the smaller cans than the larger cans to fulfill its weekly needs, then how many smaller cans are required to fulfill its weekly needs? A) 60 B) 70 C) 80 D) 100 E) 120 The OA is D. I am stuck here. I couldn't do it. I need help from experts. Thanks.

Hi Vincen, This question question is an example of a 'system' algebra question - but it can actually be solved in a variety of different ways, including Algebraically and by TESTing THE ANSWERS. If you recognize the ratio that exists begin the two sizes of cans, then you can also use that pattern to your advantage... 6 (25-ounce cans) = 150 ounces 10 (15-ounce cans) = 150 ounces You can use THAT ratio (6:10) to work through this question relatively quickly... 6 and 10 = 4 more of the smaller cans 12 and 20 = 8 more of the smaller cans 18 and 30 = 12 more of the smaller cans Etc. We're told that the number of smaller cans that are needed would be 40 more than the number of larger cans. That would be... 6(10) and 10(10) = 60 and 100 = 40 more smaller cans 100 smaller cans would be needed Final Answer: D GMAT assassins aren't born, they're made, Rich

Vincen wrote:Each week a restaurant serving Mexican food uses the same volume of chili paste, which comes in either 25-ounce cans or 15-ounce cans of chili paste. If the restaurant must order 40 more of the smaller cans than the larger cans to fulfill its weekly needs, then how many smaller cans are required to fulfill its weekly needs? A) 60 B) 70 C) 80 D) 100 E) 120 We can let the number of 25-ounce cans = x, and thus the number of 15-ounce cans = x + 40 and we can create the following equations: 25x = 15(x + 40) 25x = 15x + 600 10x = 600 x = 60 We see that we need 60 larger cans of chili paste. Since the number of smaller cans of chili paste is 40 more than the number of larger cans of chili paste, we need 100 smaller cans of chili paste. Answer: D

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