BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Each of the digits 7, 5, 8, 9 and 4 is used only one to form a three digit integer and a two digit integer. If the sum

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Moderator
Posts: 2058
Joined: Sun Oct 29, 2017 4:24 amFollowed by: 5 members
Thanked: 1 times
by M7MBA » Thu Oct 29, 2020 12:56 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

Each of the digits 7, 5, 8, 9 and 4 is used only one to form a three digit integer and a two digit integer. If the sum of the integers is 555, how many such pairs of integers can be formed?

A. 1
B. 2
C. 3
D. 4
E. 5

Answer: D

Source: GMAT Prep
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 2545
Joined: Sun Oct 29, 2017 2:04 pmFollowed by: 6 members

Re: Each of the digits 7, 5, 8, 9 and 4 is used only one to form a three digit integer and a two digit integer. If the s

by swerve » Fri Oct 30, 2020 5:41 am
M7MBA wrote: ↑
Thu Oct 29, 2020 12:56 pm
 Each of the digits 7, 5, 8, 9 and 4 is used only one to form a three digit integer and a two digit integer. If the sum of the integers is 555, how many such pairs of integers can be formed?

A. 1
B. 2
C. 3
D. 4
E. 5

Answer: D

Source: GMAT Prep
From the question, we can deduce that

1) The Hundreds place will consist of \(4 + 1\)(carried forward)
2) The Units place can ONLY have \(8\) and \(7\) as no other pair of digits can form the sum with units place of '\(5\)'
3) Thus leaving us with 9 and 5 as Tens place

Now, The number of ways to arrange Units place \(= 2!\)
and the number of ways to arrange Tens place \(= 2!\)

Since both are independent events, then the total number of arrangements is \(= 2! \cdot 2! = 4\)

Therefore, D
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1