NandishSS wrote:Each of the 15 boxes in a certain warehouse is either 5 pounds or 10 pounds, and the average (arithmetic mean) weight of the boxes in the warehouse is 8 pounds. If the average weight of the boxes in the warehouse is 8 pounds also by removing 5 boxes, how many 10-pound boxes must be removed?
(A) 1 (B) 2 (C) 3 (D) 4 (E) 5
Total weight of the 15 boxes = (number of boxes)(average weight) = 15*8 = 120 pounds.
After 5 boxes are removed, the total weight of the remaining 10 boxes = (number of remaining boxes)(average weight) = 10*8 = 80.
Thus, the total weight of the 5 removed boxes = (total weight of all 15 boxes) - (total weight of the remaining 10 boxes) = 120-80 = 40.
We can PLUG IN THE ANSWERS, which represent the number of 10-pounds boxes that must be removed.
B: 2 10-pound boxes, implying 3 5-pound boxes
Total weight removed = (2*10 + 3*5) = 35.
The total weight removed is TOO SMALL.
D: 4 10-pound boxes, implying 1 5-pound box
Total weight removed = (4*10 + 5) = 45.
The total weight removed is TOO GREAT.
Since 2 10-pounds boxes yield a total weight removed that is TOO SMALL, while 4 10-pound boxes yield a total weight removed that is TOO GREAT, the correct answer must be BETWEEN 2 AND 4.
The correct answer is
C.
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