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Source: — Data Sufficiency |
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by anshumishra » Sat Jan 22, 2011 4:17 pm
GHong14 wrote:Image
a<=b<=c<=d<=e
a +b + c+d + e = 124*5 = 620
c = 140
what is max(a) ?

For maximum value of a, a=b and c=d=e=140
So, max(a) = (620 - 3*140)/2 = 200/2 = 100.
Thanks
Anshu

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