DS

Did you copy the question correctly? Please check the first statement to see if it is x+y=z. Thanks.

@ ankanas .. DS questions go in the DS section ..

@ gmatz .. i have deleted the 2 extra posts that u posted ...

PS : - Welcome to BTG both of you ..

Looks like there is something wrong with the question. If not, I'm missing something very obvious here.

Since z is the diagonal, it has to be largest side formed by the triangle xyz.

But x-y = z implies that x is greater than z.

karthick451 wrote:Looks like there is something wrong with the question. If not, I'm missing something very obvious here.

Since z is the diagonal, it has to be largest side formed by the triangle xyz.

But x-y = z implies that x is greater than z.

Thats right. The question seems wrong. Here is why, mathematically:

x - y = z ...........(a)
x^2 + y^2 = z^2 ...........(b)

squaring both sides of (a), we get:
x^2 + y^2 - 2xy = z^2 .........(c)

subtracting (c) from (b), we get:
2xy = 0

which is impossible, unless ABCD is a line instead of a rectangle.

The explanation provided by some 'guest' above is wrong in more than one places...

The square root of x^2-2xy+y^2 is (x+y) NOPE, its x-y
x^2-2xy+y^2=49 where did you get the 49 from? Thats not a 7, thats a z as in zebra...

Oh...! I forgot to log in when I posted the solution..

Well, I too was not able to figure out how x^2-2xy+y^2=49.. The reason why I posted it here. Looks like the question is wrong...!

Thanks...!

Ankana