ds

ketkoag wrote:X*y*z<>0, yz=0?
1) x*(y+z)=0
2) (x+y*z)=0

Looks like D

If yes, I will be happy to explain..If not, i will be happy to learn

iamcste wrote:

ketkoag wrote:X*y*z<>0, yz=0?
1) x*(y+z)=0
2) (x+y*z)=0

Looks like D

If yes, I will be happy to explain..If not, i will be happy to learn

I'm afraid that the OA to this question is missing, but m pretty sure that D would be the answer.. x, y, z can not be 0 as per the question statement, right? Now if we take statement 1 then for it to be true y and z must be equal and opposite.. so by this yz can never be 0.. hence suff.

By 2, for this statement to be true x and yz must be equal and opposite..and still yz can not be 0 in any case. hence suff.

hence D, please lemme know if i am missing something here..

If X*y*z<>0, yz=0?
If If X*y*z<>0, then yz will never be zero in any case. We don't even need options for this.

guys, what does this symbol <> mean..dumb question I know:)

the symbol <> means that xyz cannot be 0. it is greater than 0 or less than 0 but not 0. that means x, y, z can never be zero..