If a≠0, is a<0?
(1)(a+b-c)/a<0
(2)c>b
OA is C.
Detailed explanations would be appreciated. Thanks
(1)(a+b-c)/a<0
(2)c>b
OA is C.
Detailed explanations would be appreciated. Thanks
Lets start with the easier stat 2. It is clearly insufficient but it tells us that :
c>b
c-b > 0
b-c < 0 {multiply by -1 and flip}
stat-1 : -> this is also insufficient alone as we don't know the values of B and C.
combining :
(a+b-c) /a < 0
from stat 2-> (b-c) will always be a -ve quantity.
Thus when a is negative the expression on the LHS of the inequality will always be positive.
suppose a = -6 , taking any -ve value of b-c you will get the negative sign on the numerator and denominator cancelled.
On the other hand if we take a as positive then the inequality will hold true until |b-c| > a
for example when b-c = -8 and a = 6 the expression is -1/3 {stat 1 does hold} whereas
b-c = -6 and a = 8 the expression is 1/3
we have 2 values when a is positive and a single value when a is negative hence answer is A is always negative. Lemme know if the trash language above is unclear.
