If n and k are positive integers, is n divisible by 6?
(1) n = k(k + 1)(k - 1)
(2) k -1 is a multiple of 3.
For statement 1, I understand that it is sufficient because -
n is a product of three consecutive terms .
And the sum of three consecutive terms is always divisible by 6
But if k=1, then n=0. In such a case the statement-1 is not sufficient.
Please let me know if i am missing something here. The question doesn’t mention that k>1.
Thanks.
(1) n = k(k + 1)(k - 1)
(2) k -1 is a multiple of 3.
For statement 1, I understand that it is sufficient because -
n is a product of three consecutive terms .
And the sum of three consecutive terms is always divisible by 6
But if k=1, then n=0. In such a case the statement-1 is not sufficient.
Please let me know if i am missing something here. The question doesn’t mention that k>1.
Thanks.
